The+Good,+The+Bad,+The+Ugly

**Well, well....well....ummmm...here we go :)**
V The Ugly: "The Hulk" Ok, I understand that the Hulk may be a super mutant due to radiation. The physics surrounding his jump in a scene where he escapes the Nevada desert are just impossible and immense in size. Let's begin with the facts: The Hulk approx. weighs 800lbs, and is 9ft in height. The Hulk can approx. jump over 7 miles (we'll assume it's actually 7.071miles to make better rounding) at a 45 degree angle in a single leap. 7.071 miles= 11,379.7 meters D=1,1379.7m V//i=// 1,137.97m/s V//f//= -1,137.97m/s

To put this in better terms, the Hulk is jumping with a velocity of 508.61mph! <---THIS IS UGLY So... Let us assume he is still jumping at a 45 degree angle with a velocity of 1,137.97. The Components of the x and y axis are as followed, Velocity in the x-axis is (Cos(45)1137.97m/s)=804.672m/s Velocity in the y-axis is (Sin(45)1137.97m/s)=804.672m/s Now how high is his jump? Well if we take the value of the initial velocity in the y-axis and our acceleration which in projectiles is always -9.8m/s squared. Now the peak of his jump will be equal to the initial y-axis velocity divided by the acceleration. Time of Peak=__804.672m/s__ =82.10s is the amount of time it takes for him to achieve the peak of his jump. -9.8m/s squared So the height of his jump is... Dy=804.672m/s*82.1s+(.5*-9.8m/s squared*(82.1 squared)) Dy=66,063.5712m+33,028m Dy=99,091m....which is 61.58miles<-ummmm...yep that is pretty much crazy [|Hulk]

The Bad: "Shaolin Soccer" Martial Arts is great, and when combined with soccer and some cheap special effects from the CGI department, makes for awesome physics examples. The main character is such an amazing kicker that he launches a soccer ball in the air for one hour! Let me tell you, that is one hell of a kick! All the data we have is the time and acceleration. T=1hr a=-9.8m/s If the total flight time was one hour than the peak of the kick was at exactly 30mins, to find this I must use our time equation, but move somethings around before I use it. T=the square root of 2D over acceleration. I want D, so the equations will be.. D= T squared times acceleration all over 2 Now we plug in our values, D= __(1800s squared times -9.8m/s squared)__=15,876,000m or 15876km or 9866miles! 2 The average distance form the earth to the moon is 384,403 km. If we take this calculation that I found we would have almost a 1/20th way to the moon! [|2:23 into the clip]

The Good: "Extreme Blobbing in Switzerland" So there is this sport called blobbing, it's basically a giant inflated mattress that transfers the gravitational potential energy of one or more bodies into the kinetic energy of another single mass. It's pretty awesome to see and even greater to do in the summer, not for the faint of heart though. Perfect landing for him! Ok... Let's get started Let us assume that the to people jumping had a mass of 660kgs (roughly 300lbs) and that they are roughly 30ft (98.4 meters)

PE of Gravity= the weight of the object * the height of the object PE of gravity= 6474.6N * 98.4 meters= 637100 Joules Also, KE= .5m*velocity squared, and if the transfer of energy was a closed system then.. (637100J*.5*300kg)square rooted= v Oops? 9775m/s=Velocity???? Oh well, hey you know what i was aiming at anyways. [|Blobbing!]